document.write( "Question 534044: The product of second and third of 3 consecutive integers is 3 more than 3 times the second integer. find the 3 integers \n" ); document.write( "
Algebra.Com's Answer #351257 by boilpoil(127) You can put this solution on YOUR website! Let x be the first integer \n" ); document.write( "Then x+1 be the second \n" ); document.write( "And x+2 be the third\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "x=+-2 ---Sorry can't enter the +_ Sign\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the first integer is either 2 or -2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The second integer \n" ); document.write( "=+-2+1 \n" ); document.write( "=3/-1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The third integer \n" ); document.write( "=+-3+1 \n" ); document.write( "=4/0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Filtering out: \n" ); document.write( "3(4)=3(3)+3 \n" ); document.write( "12=9+3 \n" ); document.write( "12=12 \n" ); document.write( "TRUE\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3(-1)=3(0)+3 \n" ); document.write( "-3=0+3 \n" ); document.write( "-3=3 \n" ); document.write( "FALSE\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the three integers are 3, 4 and 5 \n" ); document.write( " |