document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=534045>Question 534045</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two bike riders ride around a circular path, the first rider completes one round in 10 minutes and the second rider completes it in 12 minutes.  If they both start at the same place and at the same time and go in the same direction, after how many minutes will they meet again at the starting place? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #351241 by </B><A HREF=/tutors/aboutme.mpl?userid=josmiceli><B>josmiceli(19441)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josmiceli><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=josmiceli><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=351241\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The 1st rider will be back at the start every<BR>\n" );
document.write( "10 minutes, that is 10 min, 20 min, 30 min, etc.<BR>\n" );
document.write( "The 2nd rider arrives at start 2 minutes later<BR>\n" );
document.write( "each times around. The 5th time around, rider<BR>\n" );
document.write( "#2 is behind 10 minutes. <BR>\n" );
document.write( "#2 has gone 5 times around in  12*5 = 60  min<BR>\n" );
document.write( "In 60 min, rider #1 has gone 6 times around,<BR>\n" );
document.write( "and they meet at start<BR>\n" );
document.write( "The answer is 60 min or 1 hr </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );