document.write( "Question 533933: a garden is shaped like a rectangle whose perimeter is 78 ft. The length is 9 ft more than the width than the width. find the lenth and width \n" ); document.write( "

Algebra.Com's Answer #351206 by fcabanski(1391) $\"\"$ $\"About$

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\n" ); document.write( "\n" ); document.write( "You know the perimeter of a rectangle is the length of all the sides.\r
\n" ); document.write( "\n" ); document.write( "L+L+W+W = 2L+2W = P\r
\n" ); document.write( "\n" ); document.write( "P = 78\r
\n" ); document.write( "\n" ); document.write( "W is unknown, so call it X.\r
\n" ); document.write( "\n" ); document.write( "L is unknown, but it's 9 feet more than the W so call it X+9.\r
\n" ); document.write( "\n" ); document.write( "Plug all of these into the formula.\r
\n" ); document.write( "\n" ); document.write( "2(X+9) + 2X = 78 (multiply 2 by what's inside the ())\r
\n" ); document.write( "\n" ); document.write( "2X + 18 + 2X = 78 (combine like terms)\r
\n" ); document.write( "\n" ); document.write( "4X + 18 = 78 (Subtract 18 from both sides)\r
\n" ); document.write( "\n" ); document.write( "4X + 18 - 18 = 78 - 18 ---> 4X = 60 (divide both sides by 4)\r
\n" ); document.write( "\n" ); document.write( "4X/4 = 60/4 ---> X = 15\r
\n" ); document.write( "\n" ); document.write( "W = X = 15 (width)
\n" ); document.write( "L = W + 9 = X + 9 = 15 + 9 = 24.\r
\n" ); document.write( "\n" ); document.write( "Check those in the formula to ensure the P comes to 78.\r
\n" ); document.write( "\n" ); document.write( "15 + 15 + 24 + 24 = 78 HURRAH!\r
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