document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=533422>Question 533422</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two angles of a triangle have the same measure. The sum of the measures of these angles is one-half of the third angle. Can you help me find the measures of the angles? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #351186 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=351186\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let A = the measure of the first two angles<BR>\n" );
document.write( "The 3rd angle will be 180 - A - A = 180 - 2A<BR>\n" );
document.write( "Given: sum of the first two is 1/2 the 3rd:<BR>\n" );
document.write( "2A = (180 - 2A)/2<BR>\n" );
document.write( "Solve for A:<BR>\n" );
document.write( "4A = 180 - 2A<BR>\n" );
document.write( "6A = 180 <BR>\n" );
document.write( "A = 30<BR>\n" );
document.write( "So the angles are 30, 30 and 120 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );