document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=533861>Question 533861</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the system of equations using substitution.\r<BR>\n" );
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document.write( "y = 4x + 10<BR>\n" );
document.write( "y = 3x + 7\r<BR>\n" );
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document.write( "Please Explain how you go the answer! Thank You!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #351178 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=351178\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> y = 4x + 10 (equation 1)<BR>\n" );
document.write( "y = 3x + 7  (equation 2)<BR>\n" );
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document.write( "Plug definition of y from equation 2 into equation 1 and solve for x:<BR>\n" );
document.write( "3x + 7 = 4x + 10<BR>\n" );
document.write( "7 = x + 10<BR>\n" );
document.write( "-3 = x<BR>\n" );
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document.write( "Plug definition of x above into equation 2 to find y:<BR>\n" );
document.write( "y = 3x + 7 <BR>\n" );
document.write( "y = 3(-3) + 7 <BR>\n" );
document.write( "y = -9 + 7 <BR>\n" );
document.write( "y = -2<BR>\n" );
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document.write( "Answer:<BR>\n" );
document.write( "x = -3<BR>\n" );
document.write( "y = -2 </SPAN>\n" );
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