document.write( "Question 533773: two alcohol substances, a 15% solution and a 45% solution. How much of each solution should be used to obtain 300 milliliters of a 25% solution? \n" ); document.write( "
Algebra.Com's Answer #351161 by mananth(16946)\"\" \"About 
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percent ---------------- quantity
\n" ); document.write( "Alcohol I 15 ---------------- x ml
\n" ); document.write( "Alcohol II 45 ------ 300 - x ml
\n" ); document.write( "Mixture 25.00% ---------------- 300
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\n" ); document.write( "15x+45(300-x)=25*300
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\n" ); document.write( "15x+13500-45x =7500
\n" ); document.write( "15 x - 45 x= 7500 - 13500
\n" ); document.write( "-30 x= -6000
\n" ); document.write( "/ -30
\n" ); document.write( "x =200 ml 15.00% Alcohol I
\n" ); document.write( "100 ml 45.00% Alcohol II
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