document.write( "Question 533773: two alcohol substances, a 15% solution and a 45% solution. How much of each solution should be used to obtain 300 milliliters of a 25% solution? \n" ); document.write( "
Algebra.Com's Answer #351161 by mananth(16946)![]() ![]() You can put this solution on YOUR website! percent ---------------- quantity \n" ); document.write( "Alcohol I 15 ---------------- x ml \n" ); document.write( "Alcohol II 45 ------ 300 - x ml \n" ); document.write( "Mixture 25.00% ---------------- 300 \n" ); document.write( " \n" ); document.write( "15x+45(300-x)=25*300 \n" ); document.write( " \n" ); document.write( "15x+13500-45x =7500 \n" ); document.write( "15 x - 45 x= 7500 - 13500 \n" ); document.write( "-30 x= -6000 \n" ); document.write( "/ -30 \n" ); document.write( "x =200 ml 15.00% Alcohol I \n" ); document.write( "100 ml 45.00% Alcohol II \n" ); document.write( " \n" ); document.write( " |