document.write( "Question 533674: If lisa and fred spent 15.30 but lisa spent 3.50 more than fred, how much each spent? Thanks \n" ); document.write( "
Algebra.Com's Answer #351112 by Maths68(1474)\"\" \"About 
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Let
\n" ); document.write( "Lisa spent = l
\n" ); document.write( "Fred Spent = f\r
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\n" ); document.write( "\n" ); document.write( "lisa and fred spent 15.30
\n" ); document.write( "l+f=15.30.........(1)\r
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\n" ); document.write( "\n" ); document.write( "lisa spent 3.50 more than fred
\n" ); document.write( "l = f + 3.50.........(2)\r
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\n" ); document.write( "\n" ); document.write( "Put the value of l in (1)
\n" ); document.write( "f+3.50+f=15.30
\n" ); document.write( "2f=15.30-3.50
\n" ); document.write( "2f=11.80
\n" ); document.write( "f=11.80/2
\n" ); document.write( "f=5.90
\n" ); document.write( "Plug in the value of f in (2)
\n" ); document.write( "l = f + 3.50
\n" ); document.write( "l = 5.90 + 3.50
\n" ); document.write( "l = 9.4\r
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\n" ); document.write( "\n" ); document.write( "Lisa spent = l = 9.4
\n" ); document.write( "Fred Spent = f = 5.90
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