document.write( "Question 533546: Please hep with this word problem - thanks:\r
\n" ); document.write( "\n" ); document.write( "At 10am, a car leaves a hiuse traveling 60 mph. At the same time, another car leaves the same house traveling 50 mph in the opposite direction. At what time will the cars be 330 miles apart?
\n" ); document.write( "

Algebra.Com's Answer #351081 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Use the distance formula:
\n" ); document.write( "\"d+=+rt\" where: d = distance traveled, r = rate or speed of travel, and t = the time spent in traveling.
\n" ); document.write( "For the first car:
\n" ); document.write( "\"d%5B1%5D+=+r%5B1%5D%2At%5B1%5D\" Substitute: \"r%5B1%5D+=+60\" so...
\n" ); document.write( "\"d%5B1%5D+=+60t%5B1%5D\"
\n" ); document.write( "For the second car:
\n" ); document.write( "\"d%5B2%5D+=+r%5B2%5D%2At%5B2%5D\" Substitute: \"r%5B2%5D+=+50\" so...
\n" ); document.write( "\"d%5B2%5D+=+50t%5B2%5D\"
\n" ); document.write( "Now since you want the time at which these cars will be 330 miles apart,
\n" ); document.write( "\"t%5B1%5D+=+t%5B2%5D\"=\"t\" and \"d%5B1%5D%2Bd%5B2%5D+=+330\"
\n" ); document.write( "\"60t%2B50t+=+330\"
\n" ); document.write( "\"110t+=+330\"
\n" ); document.write( "\"t+=+3\"hours.
\n" ); document.write( "Add this to the starting time of 10:00am to get 1:00pm
\n" ); document.write( "
\n" );