document.write( "Question 532455: The sum of the digits of a two-digit number is 14. When the digits are reversed, the new number is 36 more than the original number. What is the original number? \n" ); document.write( "
Algebra.Com's Answer #351063 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
The sum of the digits of a two-digit number is 14. When the digits are reversed, the new number is 36 more than the original number. What is the original number?
\n" ); document.write( "**
\n" ); document.write( "let x=one's digit
\n" ); document.write( "let t=ten's digit
\n" ); document.write( "x+t=14 (eq 1)
\n" ); document.write( "x=14-t
\n" ); document.write( "..
\n" ); document.write( "original number=x+10t
\n" ); document.write( "reversed new number=10x+t
\n" ); document.write( "reversed new number-original number=36
\n" ); document.write( "10x+t-x-10t=36
\n" ); document.write( "9x-9t=36 (eq 2)
\n" ); document.write( "x+t=14 (eq 1)
\n" ); document.write( "multiply (eq 1) by 9
\n" ); document.write( "9x+9t=126 (eq 3)
\n" ); document.write( "add (eq 2) and (eq 3)
\n" ); document.write( "18x=162
\n" ); document.write( "x=9
\n" ); document.write( "t=14-x=5
\n" ); document.write( "ans:
\n" ); document.write( "original number=59
\n" ); document.write( "new number=95
\n" ); document.write( "
\n" );