document.write( "Question 52591: How many quarts of a pure solution must be added to a 5% solution to get 4 quarts of a 14.5% solution?
\n" ); document.write( "Find equation(s) and solve.
\n" ); document.write( "Not out of text book! \n" ); document.write( "
Algebra.Com's Answer #35106 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
How many quarts of a pure solution must be added to a 5% solution to get 4 quarts of a 14.5% solution?\r
\n" ); document.write( "\n" ); document.write( "Convert the decimal to % solutions:
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\n" ); document.write( "We know that the amounts of the the two solutions add up 4 qt
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\n" ); document.write( "Let x = amt of pure solution
\n" ); document.write( "Pure solution is 1.00(x)
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\n" ); document.write( "Therefore the 5% solution amt is: .05[4-x]
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\n" ); document.write( "The resulting solution: .145(4)\r
\n" ); document.write( "\n" ); document.write( "The equation: .05[4-x] + 1.00[x] = .145(4)
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\n" ); document.write( "Mult, get rid of the brackets:
\n" ); document.write( " .2 - .05x + 1x = .58
\n" ); document.write( " 1x - .05x = .58 - .2
\n" ); document.write( " .95x = .38
\n" ); document.write( " x = .38/.95
\n" ); document.write( " x = .4 qts of pure solution must be added
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\n" ); document.write( "Check by substitution: 5% amt = 4 - .4 = 3.6 qts
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\n" ); document.write( " .05(3.6) + .4 = .145[4)
\n" ); document.write( " .18 + .4 = .58 proves our value for x\r
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