document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=533160>Question 533160</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A train moving at 45 kph meets and is passed by a train moving at 36 kph.  If it takes the second train 6 seconds to pass any point of the first train, how long is the second train? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #351010 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=351010\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the combined speed of both trains =45+36= 81 kph\r<BR>\n" );
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document.write( "time taken by second train  to pass the first train completely is 6 second\r<BR>\n" );
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document.write( "6/3600 = 1/600 hours\r<BR>\n" );
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document.write( "Distance = speed * time\r<BR>\n" );
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document.write( "speed = 81 kph<BR>\n" );
document.write( "time = 1/600 hour\r<BR>\n" );
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document.write( "d= (81*1/600 )<BR>\n" );
document.write( "d= 0.135 km<BR>\n" );
document.write( "d= 0.135 *1000 = 135 meters </SPAN>\n" );
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