document.write( "Question 533171: a line that passes throught (-6,1) and is parallel to x-15-3y=0 \n" ); document.write( "
Algebra.Com's Answer #351008 by mananth(16946)\"\" \"About 
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x-3y-15=0
\n" ); document.write( "make y the subject
\n" ); document.write( "3y=x-15
\n" ); document.write( "Find the slope of this line
\n" ); document.write( "Divide by -3
\n" ); document.write( " y = 1/3 x -5
\n" ); document.write( "Compare this equation with y=mx+b
\n" ); document.write( "slope m =1/3
\n" ); document.write( "The slope of a line parallel to the above line will be the same
\n" ); document.write( "The slope of the required line will be 1/3
\n" ); document.write( "m= 1/3 ,point ( -6 , 1 )
\n" ); document.write( "Find b by plugging the values of m & the point in
\n" ); document.write( "y=mx+b
\n" ); document.write( "1 = -2.00 + b
\n" ); document.write( "b= 3
\n" ); document.write( "m= 1/3
\n" ); document.write( "Plug value of the slope and b in y = mx +b
\n" ); document.write( "The required equation is y = 1/3 x+3
\n" ); document.write( " y = 1/ 3 x + 3
\n" ); document.write( "m.ananth@hotmail.ca
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