document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=533196>Question 533196</A>: <I><SPAN STYLE=\"word-break: break-all;\"> My syllabus gives these co-ordinance as the solution but I don't understand how they got this answer?\r<BR>\n" );
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document.write( "2x + y = 17<BR>\n" );
document.write( "y = 6x + 1<BR>\n" );
document.write( "x = 2, y = 13\r<BR>\n" );
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document.write( "Thanks<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #351003 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16949)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=351003\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2x + y = 17<BR>\n" );
document.write( "y = 6x + 1\r<BR>\n" );
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document.write( "y= 2x+1\r<BR>\n" );
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document.write( "substitute y in the first equation\r<BR>\n" );
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document.write( "2x+(6x+1)=17<BR>\n" );
document.write( "8x+1=17<BR>\n" );
document.write( "-1 on both sides\r<BR>\n" );
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document.write( "8x+1-1=17-1<BR>\n" );
document.write( "8x=16<BR>\n" );
document.write( "/2<BR>\n" );
document.write( "x=2<BR>\n" );
document.write( "Plug x=2 in y=2x+1\r<BR>\n" );
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document.write( "y=6*2+1 <BR>\n" );
document.write( "y=13\r<BR>\n" );
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