document.write( "Question 6491: While traveling with the wind a plane flies 300 miles in 40 minutes. It returns against the wind in 45 minutes. Find the air speed of the plane and the rate of the wind. Use a system of equations to solve the problem \n" ); document.write( "
Algebra.Com's Answer #3510 by srinivas123(23)![]() ![]() ![]() You can put this solution on YOUR website! While traveling with the wind a plane flies 300 miles in 40 minutes. It returns against the wind in 45 minutes. Find the air speed of the plane and the rate of the wind. Use a system of equations to solve the problem\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let the speed of plane be X \n" ); document.write( "Let the speed of air be Y\r \n" ); document.write( "\n" ); document.write( "Total distance covered = 300miles .\r \n" ); document.write( "\n" ); document.write( "while going along the wind the speeds add. \n" ); document.write( "Total speed of plane is X+Y \n" ); document.write( "Time taken = 40 mins or 2/3 hour. \n" ); document.write( "time = distance/speed.\r \n" ); document.write( "\n" ); document.write( "so 2/3 = 300 /(x+y)\r \n" ); document.write( "\n" ); document.write( "----> 2(X+Y)=3*300 \n" ); document.write( "----> 2(X+Y)=900 \n" ); document.write( "----> X+Y = 450 equation (1).\r \n" ); document.write( "\n" ); document.write( "While going against the wind the speeds are subtracted since wind is opposing you.\r \n" ); document.write( "\n" ); document.write( "Time taken to return = 45mins ---->3/4 hour.\r \n" ); document.write( "\n" ); document.write( "Distance = 300 miles .\r \n" ); document.write( "\n" ); document.write( "Time = distance/speed.\r \n" ); document.write( "\n" ); document.write( "So,\r \n" ); document.write( "\n" ); document.write( "3/4 = 300/(X-Y) \n" ); document.write( "----> 3(X-Y)=4*300 \n" ); document.write( "----> X-Y = 1200/3 ----> X-Y = 400 equation (2).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "adding equation (1) and (2) we get \n" ); document.write( " X+Y=450 \n" ); document.write( "(+) X-Y=400\r \n" ); document.write( "\n" ); document.write( "2X=850 ----> X=425 miles / hour. \n" ); document.write( "Substituting this value in Equation (1) we get Y=25 miles/hour .\r \n" ); document.write( "\n" ); document.write( "Hence speed of plane is 425 miles/hour and speed of air is 25 miles/hour \n" ); document.write( " |