document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=532973>Question 532973</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help, I'm confused on this problem.\r<BR>\n" );
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document.write( "log(base2)x = log(base4)(2x-1)    \r<BR>\n" );
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document.write( "Solve for x.\r<BR>\n" );
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document.write( "Thanks. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #350995 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=350995\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Please help, I'm confused on this problem. <BR>\n" );
document.write( "log(base2)x = log(base4)(2x-1) <BR>\n" );
document.write( "Solve for x.<BR>\n" );
document.write( "**<BR>\n" );
document.write( "log(base2)x = log(base4)(2x-1)<BR>\n" );
document.write( "change to a common base(2)<BR>\n" );
document.write( "log of the number with the new base(2) divided by log of the old base(4) with the new base(2).<BR>\n" );
document.write( "log2(x)=log2(2x-1)/log2(4)<BR>\n" );
document.write( "log2(4)=2<BR>\n" );
document.write( "log2(x)=log2(2x-1)/2<BR>\n" );
document.write( "2log2(x)-log2(2x-1)=0<BR>\n" );
document.write( "log2(x^2)-log2(2x-1)=0<BR>\n" );
document.write( "place under single log<BR>\n" );
document.write( "log2[(x^2)/(2x-1)]=0<BR>\n" );
document.write( "convert to exponential form: base(2) raised to log of number(0)=number(x^2)/(2x-1)<BR>\n" );
document.write( "2^0=(x^2)/(2x-1)=1<BR>\n" );
document.write( "x^2=2x-1<BR>\n" );
document.write( "x^2-2x+1=0<BR>\n" );
document.write( "(x-1)^2=0<BR>\n" );
document.write( "x=1 (multiplicity 2) </SPAN>\n" );
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