document.write( "Question 533141: I can't figure out where to even start with this problem. Any help would be greatly appreciated.\r
\n" ); document.write( "\n" ); document.write( "It says to solve and put my answer in a solution set.\r
\n" ); document.write( "\n" ); document.write( "(x+18)(x-3)(x+15)>0\r
\n" ); document.write( "\n" ); document.write( "thanks \n" ); document.write( "
Algebra.Com's Answer #350980 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
I can't figure out where to even start with this problem. Any help would be greatly appreciated.
\n" ); document.write( "It says to solve and put my answer in a solution set.
\n" ); document.write( "(x+18)(x-3)(x+15)>0
\n" ); document.write( "**
\n" ); document.write( "f(x)=(x+18)(x-3)(x+15)
\n" ); document.write( "Draw a number line with all the zeros in it:
\n" ); document.write( "<...-....-18.....+....-15......-.......3.....+.....>
\n" ); document.write( "By inspection of the factors, you can see that when x>3, f(x)>0.
\n" ); document.write( "As you move to the left thru the remaining factors, f(x) switches signs as we go thru a zero of odd multiplicity like 1,3,5, etc. All zeros in this case are of multiplicity 1. The signs of the different intervals can be verified by plugging in x-values within the intervals.
\n" ); document.write( "Solution in interval notation:
\n" ); document.write( "(-18,-15) U (3,∞) \n" ); document.write( "
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