document.write( "Question 533133: How many mg of a metal containing 45% nickel must be combined with 6 mg of pure nickel to form an alloy containing 78% nickel? \n" ); document.write( "

Algebra.Com's Answer #350975 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let $\"+x+\"$ = mg of a metal containing 45% nickel
\n" ); document.write( " $\"+.45x+\"$ = mg of pure nickel in 45% alloy
\n" ); document.write( "----------
\n" ); document.write( " $\"+%28+.45x+%2B+6+%29+%2F+%28+x+%2B+6+%29+=+.78+\"$
\n" ); document.write( " $\"+.45x+%2B+6+=+.78%2A%28+x+%2B+6+%29+\"$
\n" ); document.write( " $\"+.45x+%2B+6+=+.78x+%2B+4.68+\"$
\n" ); document.write( " $\"+.78x+-+.45x+=+6+-+4.68+\"$
\n" ); document.write( " $\"+.33x+=+1.32+\"$
\n" ); document.write( " $\"+x+=+4+\"$
\n" ); document.write( "4 mg of 45% nickel metal must be added
\n" ); document.write( "check:
\n" ); document.write( " $\"+%28+.45%2A4+%2B+6+%29+%2F+%28+4+%2B+6+%29+=+.78+\"$
\n" ); document.write( " $\"+%28+1.8+%2B+6+%29+%2F+10+=+.78+\"$
\n" ); document.write( " $\"+7.8+=+.78%2A10+\"$
\n" ); document.write( " $\"+7.8+=+7.8+\"$
\n" ); document.write( "OK\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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