document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=532972>Question 532972</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the system using the addition method.  If there is no solution or if there are many solutions and the system's equations are dependent, so state.  The three equations are:\r<BR>\n" );
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document.write( "6x-y+3z+22<BR>\n" );
document.write( "x+3y-z=-4<BR>\n" );
document.write( "3x+3y-4z=-9\r<BR>\n" );
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document.write( "I am having to do my homework on course compass (AKA mathlab) and only get 3 chances to enter in my answer before it giving me a new problem.  This is what I have done so far to get an answer and it telling me my answer is wrong.\r<BR>\n" );
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document.write( "I took equation 1 and 3 and eliminated X and got another equation which is now equation 4.  I then took equation 2 and 3 and eliminated X and got my 5th equation.  I then added equation 4 and 5 and eliminated Z which gave my my Y answer.  I then plugged my Y answer in to equation 5 and got my Z.  I then took my Y and Z answers and plugged them into equation 1 to get my X.  Somewhere in the mess of it all, I got the wrong answers.  Can you help me?\r<BR>\n" );
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document.write( "Thanks,\r<BR>\n" );
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document.write( "Lexi </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #350939 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=350939\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 4___ -7y + 11z = 40\r<BR>\n" );
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document.write( "5___ -6y - z = 3\r<BR>\n" );
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document.write( "-73y = 73 ___ y = -1\r<BR>\n" );
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document.write( "-6(-1) - z = 3 ___ z = 3\r<BR>\n" );
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document.write( "x + 3(-1) - (3) = -4 ___ x = 2 </SPAN>\n" );
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