document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=532899>Question 532899</A>: <I><SPAN STYLE=\"word-break: break-all;\"> $5,000 is invested at 3% interest. How much money must be invested at 5% interest so that the total interest from the two investments is $275 after one year?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #350932 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=350932\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> $5,000 is invested at 3% interest. How much money must be invested at 5% interest so that the total interest from the two investments is $275 after one year? <BR>\n" );
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document.write( "Interest Eq::: 0.03*5000 + 0.05x = 275<BR>\n" );
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document.write( "Multiply thru by 100 to get:<BR>\n" );
document.write( "3*5000 + 5x = 27500<BR>\n" );
document.write( "5x = 27500- 15000<BR>\n" );
document.write( "5x = 12500<BR>\n" );
document.write( "x = $2500 (amt. to invest at 5%)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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