document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=532580>Question 532580</A>: <I><SPAN STYLE=\"word-break: break-all;\"> My homework says to rationalize the denominator. I've tried another problem similar to this and I ended up getting it wrong. This is another one I'm stuck on. Cube root of 35 over the cube root of 21. I thought you had to break the top as cube roots of 5 and 7 and break the bottom as cube roots of 3 and 7 and cancel out, then multiply the top and bottom by the cube root of three. Is that the correct way to rationalize? Please and thank you!   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #350882 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=350882\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Cube root of 35 over the cube root of 21.<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=root%283%2C35%29%2Froot%283%2C21%29+=+root%283%2C35%2F21%29+=+root%283%2C5%2F3%29 ALIGN=MIDDLE  ALT=\"root%283%2C35%29%2Froot%283%2C21%29+=+root%283%2C35%2F21%29+=+root%283%2C5%2F3%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "= <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=root%283%2C45%2F27%29+=+root%283%2C45%29%2F3 ALIGN=MIDDLE  ALT=\"root%283%2C45%2F27%29+=+root%283%2C45%29%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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