document.write( "Question 532546: I'm having trouble finding the con straights to this problem.(there are 3)\r
\n" ); document.write( "\n" ); document.write( "It says there is a gold ore manufacturing company. there are 2 sections that make the ore. Section A costs $20 per ton of ore Section B costs $10. They cannot spend more than $80 and section B cannot make more than section A. How much ore can they make to maximize costs?\r
\n" ); document.write( "\n" ); document.write( "What are the con straights?
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Algebra.Com's Answer #350873 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
I think you mean, \"constraints\"
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\n" ); document.write( "It says there is a gold ore manufacturing company. there are 2 sections that make the ore.
\n" ); document.write( " Section A costs $20 per ton of ore Section B costs $10.
\n" ); document.write( " They cannot spend more than $80 and section B cannot make more than section A. How much ore can they make to maximize costs?
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\n" ); document.write( "Cost constraint
\n" ); document.write( "20A + 10B =< 80
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\n" ); document.write( "\"section B cannot make more than section A\"
\n" ); document.write( "B =< A
\n" ); document.write( "Therefore we can say B = A and use the 1st equation
\n" ); document.write( "20A + 10A =< 80
\n" ); document.write( "30A = < 80
\n" ); document.write( "A =< \"80%2F30\"
\n" ); document.write( "A =< 2.67,
\n" ); document.write( "We have to use integers. A = 3, then B = 2
\n" ); document.write( "20(3) + 10(2) = 80
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