document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=532580>Question 532580</A>: <I><SPAN STYLE=\"word-break: break-all;\"> My homework says to rationalize the denominator. I've tried another problem similar to this and I ended up getting it wrong. This is another one I'm stuck on. Cube root of 35 over the cube root of 21. I thought you had to break the top as cube roots of 5 and 7 and break the bottom as cube roots of 3 and 7 and cancel out, then multiply the top and bottom by the cube root of three. Is that the correct way to rationalize? Please and thank you!   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #350867 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=350867\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Cube root of 35 over the cube root of 21<BR>\n" );
document.write( "------<BR>\n" );
document.write( "Multiply numerator and denomator by cbrt(21^2) to get:<BR>\n" );
document.write( "----<BR>\n" );
document.write( "= cbrt(35*21^2)/cbrt(21^3)<BR>\n" );
document.write( "----<BR>\n" );
document.write( "= cbrt(7^3*5*3^2)/21<BR>\n" );
document.write( "----<BR>\n" );
document.write( "= (7/21)*cbrt(45)<BR>\n" );
document.write( "---<BR>\n" );
document.write( "= (1/3)cbrt(45)<BR>\n" );
document.write( "==================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "================== </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );