document.write( "Question 532550: A chemist needs 130 milliliters of a 39% solution but has only 3% and 55% solutions available. How many milliliters of each should be mixed to get the desired solution? \n" ); document.write( "
Algebra.Com's Answer #350862 by mananth(16946)\"\" \"About 
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---------percent ---------------- quantity
\n" ); document.write( "Solution I 3 ---------------- x ml
\n" ); document.write( "Solution II 55 ------ 130 - x ml
\n" ); document.write( "Mixture 39.00% ---------------- 130
\n" ); document.write( "
\n" ); document.write( "3 x + 55 ( 130 - x ) = 39 * 130
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\n" ); document.write( "3x+7150 -55x=5070
\n" ); document.write( "3x-55x=5070-7150
\n" ); document.write( "-52x= -2080
\n" ); document.write( "/ -52
\n" ); document.write( "x=40 ml 3.00% Solution I
\n" ); document.write( "90 ml 55.00% Solution II
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