document.write( "Question 532492: the length of a rectangle is four times its width, the area is 144 yards squared what is the perimiter? \n" ); document.write( "
Algebra.Com's Answer #350853 by jkrsmsc76(5)\"\" \"About 
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L = 4W (the length is 4 times the width\r
\n" ); document.write( "\n" ); document.write( "\"Area+=+L%2AW\"\r
\n" ); document.write( "\n" ); document.write( "so \"Area+=+4W%2AW\"\r
\n" ); document.write( "\n" ); document.write( "Since the Area is 144\r
\n" ); document.write( "\n" ); document.write( "\"144+=+4W%2AW\" or \"144=4W%5E2\"\r
\n" ); document.write( "\n" ); document.write( "Divide both sides by 4 to get \"36=W%5E2\"\r
\n" ); document.write( "\n" ); document.write( "Take the square root of both sides to get \"W=6+or+W=-6\". Since it is a length, we don't need the negative, so \"W=6\"\r
\n" ); document.write( "\n" ); document.write( "If \"W=6\" and the length is 4 times the width, \"L=4%2A6=24\".\r
\n" ); document.write( "\n" ); document.write( "We now know the width is 6 and the length is 24, so we can find the perimeter, using the perimeter formula: \"P=2L%2B2W\"\r
\n" ); document.write( "\n" ); document.write( "So \"P=2%2824%29%2B2%286%29=48%2B12=60+yards\"
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