document.write( "Question 532492: the length of a rectangle is four times its width, the area is 144 yards squared what is the perimiter? \n" ); document.write( "
Algebra.Com's Answer #350853 by jkrsmsc76(5)![]() ![]() ![]() You can put this solution on YOUR website! L = 4W (the length is 4 times the width\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "so \n" ); document.write( "\n" ); document.write( "Since the Area is 144\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Divide both sides by 4 to get \n" ); document.write( "\n" ); document.write( "Take the square root of both sides to get \n" ); document.write( "\n" ); document.write( "If \n" ); document.write( "\n" ); document.write( "We now know the width is 6 and the length is 24, so we can find the perimeter, using the perimeter formula: \n" ); document.write( "\n" ); document.write( "So |