document.write( "Question 52484: How do i prove that given triangle ABC with the altitude from B of the same length as the altitude from C, then the triangle must be isosceles.
\n" ); document.write( "I can prove this question without it saying altitude that is where i am confused.
\n" ); document.write( "thank you
\n" ); document.write( "Nadia \n" ); document.write( "
Algebra.Com's Answer #35081 by venugopalramana(3286)\"\" \"About 
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How do i prove that given triangle ABC with the altitude from B of the same length as the altitude from C, then the triangle must be isosceles.
\n" ); document.write( "I can prove this question without it saying altitude that is where i am confused.
\n" ); document.write( "altitude means perpendicular from a vertex to its opposite side..here we are
\n" ); document.write( "given
\n" ); document.write( "ABC is a triangle.
\n" ); document.write( "BE is altitude..means..E is on AC and BE is perpendicular to AC
\n" ); document.write( "CF ia altitude.........F is on AB and CF is perpendicular to AB
\n" ); document.write( "BE=CF
\n" ); document.write( "in triangles BEC and CFB,we have
\n" ); document.write( "BE=CF..given
\n" ); document.write( "angle BEC=90=ANGLE CFE...............given
\n" ); document.write( "BC=BC
\n" ); document.write( "so the 2 triangles are congruent.
\n" ); document.write( "EC=FB....similarly we can prove
\n" ); document.write( "EA=FA
\n" ); document.write( "adding
\n" ); document.write( "EC+EA = FB+FA
\n" ); document.write( "AC = AB...so ABC is isocelles triangle \n" ); document.write( "
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