document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=531889>Question 531889</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if a+b = 35<BR>\n" );
document.write( "and 2a + 4b = 94<BR>\n" );
document.write( "how do you find a and b? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #350784 by </B><A HREF=/tutors/aboutme.mpl?userid=boilpoil><B>boilpoil(127)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=boilpoil><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=boilpoil><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=350784\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a+b=35\r<BR>\n" );
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document.write( "2a+4b=94 ---You need to make b the subject to insert the equation into 'b'<BR>\n" );
document.write( "4b=94-2a<BR>\n" );
document.write( "b=(94-2a)/4\r<BR>\n" );
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document.write( "a+(94-2a)/4=35<BR>\n" );
document.write( "4a+94-2a=140<BR>\n" );
document.write( "2a=46<BR>\n" );
document.write( "a=23\r<BR>\n" );
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document.write( "b=(94-2(23))/4 ---Substitute a=23 into 'a'<BR>\n" );
document.write( "b=(94-46)/4<BR>\n" );
document.write( "b=48/4<BR>\n" );
document.write( "b=12\r<BR>\n" );
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document.write( "And 23+12=35 </SPAN>\n" );
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