document.write( "Question 531978: Find 3 consecutive numbers such that 4 times the first is equal to 7 more than the sum of the other two.\r
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document.write( "I do not understand how to work this problem. HELP! \n" );
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Algebra.Com's Answer #350737 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Find 3 consecutive numbers such that 4 times the first is equal to 7 more than the sum of the other two. \n" ); document.write( ": \n" ); document.write( "3 numbers: x, (x+1), (x+2) \n" ); document.write( ": \n" ); document.write( "Write an equation for the statement: \n" ); document.write( "\"numbers such that 4 times the first is equal to 7 more than the sum of the other two. \" \n" ); document.write( "4x = (x+1) + (x+2) + 7 \n" ); document.write( "4x = 2x + 3 + 7 \n" ); document.write( "4x = 2x + 10 \n" ); document.write( "4x - 2x = 10 \n" ); document.write( "2x = 10 \n" ); document.write( "x = 5 \n" ); document.write( ": \n" ); document.write( "The three numbers, 5, 6, 7 \n" ); document.write( ": \n" ); document.write( "Check that in the given statement: \n" ); document.write( "\"3 consecutive numbers such that 4 times the first is equal to 7 more than the sum of the other two. \" \n" ); document.write( "4(5) = 6 + 7 + 7 \n" ); document.write( " \n" ); document.write( " |