document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=532151>Question 532151</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a rectangular field is twice as long as it is wide, if the perimeter of the field is 96 yards, what are the dimensions ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #350691 by </B><A HREF=/tutors/aboutme.mpl?userid=oberobic><B>oberobic(2304)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oberobic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=350691\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P = perimeter<BR>\n" );
document.write( "L = length<BR>\n" );
document.write( "W = width<BR>\n" );
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document.write( "P = 96<BR>\n" );
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document.write( "P = 2(L+W)<BR>\n" );
document.write( "L+W = 96/2 = 48<BR>\n" );
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document.write( "L = 2W<BR>\n" );
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document.write( "substitute for L<BR>\n" );
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document.write( "2W + W = 48<BR>\n" );
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document.write( "3W = 48<BR>\n" );
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document.write( "W = 16<BR>\n" );
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document.write( "substitute W<BR>\n" );
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document.write( "L = 48-W = 32<BR>\n" );
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document.write( "L is twice W<BR>\n" );
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document.write( "Answer:  Length = 32 and width = 16.<BR>\n" );
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document.write( "Done.<BR>\n" );
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