document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=532080>Question 532080</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Ms. Niemeyer is taking the train 3,240 miles to Oregon. She will travel 1/8 the distance the first day and 1/6 the distance on the second day. How far will she have left to go after two days?\r<BR>\n" );
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document.write( "Please show me how to set up the equation. <BR>\n" );
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document.write( "Parent </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #350669 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=350669\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Ms. Niemeyer is taking the train 3,240 miles to Oregon.<BR>\n" );
document.write( " She will travel 1/8 the distance the first day and 1/6 the distance on the second day.<BR>\n" );
document.write( " How far will she have left to go after two days? <BR>\n" );
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document.write( "Let d = remaining distance after two days<BR>\n" );
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document.write( "d = 3240 - <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F8 ALIGN=MIDDLE  ALT=\"1%2F8\"   DISABLED_style= \"max-width:90%; height:auto;\" >(3240) - <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F6 ALIGN=MIDDLE  ALT=\"1%2F6\"   DISABLED_style= \"max-width:90%; height:auto;\" >(3240)<BR>\n" );
document.write( "Both of these fraction will cancel into 3240, so you have<BR>\n" );
document.write( "d = 3240 - 405 - 540<BR>\n" );
document.write( "d = 2295 mi to go </SPAN>\n" );
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