document.write( "Question 531897: A 3-men crew can do a certain job in 4 hours, while it takes a 4-men crew to do the same job 3 hours. How long will it take to complete the job if two crews work together, and one worker from the second crew was 1 hour late? Thank you \n" ); document.write( "
Algebra.Com's Answer #350654 by ankor@dixie-net.com(22740)\"\" \"About 
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A 3-men crew can do a certain job in 4 hours, while it takes a 4-men crew to do the same job 3 hours.
\n" ); document.write( "How long will it take to complete the job if two crews work together, and one worker from the second crew was 1 hour late?
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\n" ); document.write( "We know that the job requires 12 man-hours to complete (3*4 or 4*3)
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\n" ); document.write( "Let's try and determine how long it would take the 2nd crew to do the job if one guy was 1 hr late (h).
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\n" ); document.write( "3 guys work the whole time, one guy works 1 hr less
\n" ); document.write( "3h + 1(h-1) = 12
\n" ); document.write( "3h + h - 1
\n" ); document.write( "4h = 12 + 1
\n" ); document.write( "4h = 13
\n" ); document.write( "h = 13/4
\n" ); document.write( "h = 3.25 hrs to do the job under these conditions
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\n" ); document.write( "Now using a standard, shared work equation where the completed job = 1
\n" ); document.write( "Crew 1 + crew 2 = completed job
\n" ); document.write( "\"t%2F4\" + \"t%2F3.25\" = 1
\n" ); document.write( "multiply by 13 to clear the denominators
\n" ); document.write( "3.25t + 4t = 13
\n" ); document.write( "7.25t = 13
\n" ); document.write( "t = \"13%2F7.25\"
\n" ); document.write( "t = 1.793 hrs which is 1 hr + .793(60) ~ 1 hr 48 min
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\n" ); document.write( "Did this make sense? Let me know if you find out I am wrong on this one. C\r
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