document.write( "Question 531952: Solve the inequality and graph the solution set on a real number line.\r
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document.write( "(1/x+1) > (2/x-1)\r
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document.write( "Here is what I was trying:\r
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document.write( " (1/x+1) > (2/x-1)
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document.write( "-(2/x-1) > 0
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document.write( "(1/x+1)-(2/x-1) > 0
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document.write( "(1(x-1)/((x+1)(x-1))-(2(x+1)/(x+1)(x-1))>0
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document.write( "(x-1-2x-2)/((x+1)(x-1))>0
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document.write( "(-x-3)/(x+1)(x-1)>0
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document.write( "Set numerator equal to 0\r
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document.write( "-x-3=0
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document.write( "x=3
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document.write( "Set denominator equal to 0\r
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document.write( "x+1=0 x=-1\r
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document.write( "x-1=0 x=1
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document.write( "Then I got stuck! I don't even know if I was doing the first part right.
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Algebra.Com's Answer #350640 by Earlsdon(6294)![]() ![]() ![]() You can put this solution on YOUR website! Not sure how to read this without the use of parentheses! \n" ); document.write( "Is it \n" ); document.write( "or \n" ); document.write( "I'll assume the second one. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Your answer of x = 3 cannot be correct as you are dealing with inequalities. \n" ); document.write( " \n" ); document.write( " |