document.write( "Question 531952: Solve the inequality and graph the solution set on a real number line.\r
\n" ); document.write( "\n" ); document.write( "(1/x+1) > (2/x-1)\r
\n" ); document.write( "\n" ); document.write( "Here is what I was trying:\r
\n" ); document.write( "\n" ); document.write( " (1/x+1) > (2/x-1)
\n" ); document.write( "-(2/x-1) > 0
\n" ); document.write( "__________________
\n" ); document.write( "(1/x+1)-(2/x-1) > 0
\n" ); document.write( "(1(x-1)/((x+1)(x-1))-(2(x+1)/(x+1)(x-1))>0
\n" ); document.write( "________________________________________\r
\n" ); document.write( "\n" ); document.write( "(x-1-2x-2)/((x+1)(x-1))>0
\n" ); document.write( "_______________________\r
\n" ); document.write( "\n" ); document.write( "(-x-3)/(x+1)(x-1)>0
\n" ); document.write( "________________________
\n" ); document.write( "Set numerator equal to 0\r
\n" ); document.write( "\n" ); document.write( "-x-3=0
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\n" ); document.write( "x=3
\n" ); document.write( "________________________
\n" ); document.write( "Set denominator equal to 0\r
\n" ); document.write( "\n" ); document.write( "x+1=0 x=-1\r
\n" ); document.write( "\n" ); document.write( "x-1=0 x=1
\n" ); document.write( "__________________________\r
\n" ); document.write( "\n" ); document.write( "Then I got stuck! I don't even know if I was doing the first part right.
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Algebra.Com's Answer #350640 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Not sure how to read this without the use of parentheses!
\n" ); document.write( "Is it \"%281%2Fx%29%2B1+%3E+%282%2Fx%29-1\"
\n" ); document.write( "or \"1%2F%28x%2B1%29+%3E+2%2F%28x-1%29\"?
\n" ); document.write( "I'll assume the second one.
\n" ); document.write( "\"1%2F%28x%2B1%29+%3E+2%2F%28x-1%29\" Simplify.
\n" ); document.write( "\"1%2A%28x-1%29%2F%28x%2B1%29%28x-1%29+%3E+2%2A%28x%2B1%29%2F%28x%2B1%29%28x-1%29\" Multiply both sides by (x+1)(x-1) to clear the denominators.
\n" ); document.write( "\"x%2B1+%3E+2%28x-1%29\"
\n" ); document.write( "\"x%2B1+%3E+2x-2\" Subtract x from both sides.
\n" ); document.write( "\"1+%3E+x-2\" Add 2 to both sides.
\n" ); document.write( "\"3+%3E+x\" or
\n" ); document.write( "\"x+%3C+3\"
\n" ); document.write( "Your answer of x = 3 cannot be correct as you are dealing with inequalities.
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