document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=531942>Question 531942</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How much of a 50% acid solution must be mixed with 80 gallons of a 14% acid solution to obtain a solution that is 40% acid? \r<BR>\n" );
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document.write( "I feel like I've done something like this before, but I just can't get started. Thank you for any help! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #350637 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=350637\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = the required number of gallons of the 50% acid solution.<BR>\n" );
document.write( "Write the equation in terms of the amount of acid in the solution:<BR>\n" );
document.write( "For example: 80 gallons of 14% acid solution would have 0.14(80) = 11.2 gallons of acid. So...<BR>\n" );
document.write( "0.5x+0.14(80) = 0.4(80+x) Simplify and solve for x.<BR>\n" );
document.write( "0.5x+11.2 = 32+0.4x Subtract 0.4x from both sides.<BR>\n" );
document.write( "0.1x+11.2 = 32 Subtract 11.2 from both sides.<BR>\n" );
document.write( "0.1x = 20.8 Finally, divide both sides by 0.1<BR>\n" );
document.write( "x = 208 gallons of the 50% acid solution.<BR>\n" );
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