document.write( "Question 531715: If Mavis is 5 yrs older than her brother. 5 years ago she was twice her brother's age, how old are they now? \n" ); document.write( "
Algebra.Com's Answer #350559 by oberobic(2304)\"\" \"About 
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M = Mavis' age
\n" ); document.write( "B = Brother's age
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\n" ); document.write( "M = B+5
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\n" ); document.write( "Five years ago...
\n" ); document.write( "M-5
\n" ); document.write( "B-5
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\n" ); document.write( "Mavis was twice her brother's age.
\n" ); document.write( "(M-5) = 2(B-5)
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\n" ); document.write( "Substitute M = B+5
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\n" ); document.write( "(B+5-5) = 2B-10
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\n" ); document.write( "B = 2B-10
\n" ); document.write( "-B = -10
\n" ); document.write( "B = 10
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\n" ); document.write( "M = B+5 = 15
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\n" ); document.write( "Check their ages 5 years ago.
\n" ); document.write( "B = 10-5 = 5
\n" ); document.write( "M = 15-5 = 10
\n" ); document.write( "M = 2*B
\n" ); document.write( "Correct.
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\n" ); document.write( "Answer: Mavis is 15 and her brother is 10 years old.
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\n" ); document.write( "Done.
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