document.write( "Question 531626: find three consecutive integers whose sum is 9 greater than twice the largest number \n" ); document.write( "

Algebra.Com's Answer #350533 by oberobic(2304) $\"\"$ $\"About$

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Define the numbers as:
\n" ); document.write( "x
\n" ); document.write( "x+1
\n" ); document.write( "x+2
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\n" ); document.write( "x +(x+1) +(x+2) = 2(x+2) + 9
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\n" ); document.write( "3x + 3 = 2x + 4 + 9
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\n" ); document.write( "x = 10
\n" ); document.write( "x+1 = 11
\n" ); document.write( "x+2 = 12
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\n" ); document.write( "Check the answer.
\n" ); document.write( "2*12 + 9 = 24+9 = 33
\n" ); document.write( "10+11+12 = 33
\n" ); document.write( "Correct.
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\n" ); document.write( "Answer: The three integers are 10, 11, and 12.
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\n" ); document.write( "Done. \n" ); document.write( "

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