document.write( "Question 531599: x-2
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Algebra.Com's Answer #350521 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
x-2
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\n" ); document.write( "Multiply both sides by 3 to get:
\n" ); document.write( "x-2 > 12
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\n" ); document.write( "Add 2 to both sides to get:
\n" ); document.write( "x > 14
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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