document.write( "Question 531437: ______8______
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\n" ); document.write( "\n" ); document.write( "This is a paper that is cut from EACH side in small squares when you fold it is a rectangular prism with no top, 13 is the lenght and 8 is the width. it did'nt let me draw the other half but it is a FULL rectangle and all four sides of the corners a cube is cut out and that is X. What is the value of X and Maximum volume of it and could you show work too my Teacher said use a TI calculator if you can and i dont have one and she said that it was going to be a parabola it would be great if you could help me thanks!
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Algebra.Com's Answer #350482 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Once the box is folded, the length will be , the width will be , and the height will be . Since the volume of a rectangular prism is given by length times width times height, we create the volume function:\r
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\n" ); document.write( "\n" ); document.write( "The graph of which is NOT a parabola, although the portion of the graph of interest, that is where is within an interval that allows for an actual physical box to be created, sorta-kinda looks like a parabola.\r
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\n" ); document.write( "\n" ); document.write( "In order to actually create a box, must be in the interval . If were negative you would be dealing with the absurdity of cutting a negative amount from the corners. If , then you aren't cutting anything away from the corners and all you have is a flat 13 by 8 piece of paper with zero volume. If then and again, you have zero volume.\r
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\n" ); document.write( "\n" ); document.write( "Somewhere in between is a maximum volume, and we know this because of the Mean Value Theorem.\r
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\n" ); document.write( "\n" ); document.write( "If a function is continuous and twice differentiable over an interval and if the first derivitive of the function is equal to zero at some point in the interval, then there is a local extremum at that point. If the second derivitive is negative at that point, then the extremum is a maximum.\r
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\n" ); document.write( "\n" ); document.write( "Set the derivitive equal to zero:\r
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\n" ); document.write( "\n" ); document.write( "Solve this quadratic and select the value that is within the previously discussed interval. This is the value that gives the extreme volume. Evaluate the original volume function for this value to get the actual extreme volume.\r
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\n" ); document.write( "\n" ); document.write( "Take the second derivitive:\r
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\n" ); document.write( "\n" ); document.write( "and evaluate it at the value of that gives the extreme volume. The second derivitive must be negative if the extreme point is a maximum.\r
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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