document.write( "Question 531225: A hyperbola with its Center (-3,2), transverse axis parallel to the y-axis, passing through (1,7), the asymptotes are perpendicular to each other. \n" ); document.write( "
Algebra.Com's Answer #350474 by lwsshak3(11628)\"\" \"About 
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A hyperbola with its Center (-3,2), transverse axis parallel to the y-axis, passing through (1,7), the asymptotes are perpendicular to each other.
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\n" ); document.write( "Standard form of equation for a hyperbola with vertical transverse axis, as in this case:
\n" ); document.write( "(y-k)^2/a^2-(x-h)^2/b^2=1, with (h,k) being the (x,y) coordinates of the center.
\n" ); document.write( "..
\n" ); document.write( "Took me awhile to figure out that if the asymptotes are perpendicular to each other their slopes must be equal to ±1.
\n" ); document.write( "slope=a/b=±1
\n" ); document.write( "so, a=b or a=-b
\n" ); document.write( "..
\n" ); document.write( "Given equation:
\n" ); document.write( "(y-2)^2/a^2-(x+3)^2/b^2=1
\n" ); document.write( "can be rewritten:
\n" ); document.write( "(y-2)^2/a^2-(x+3)^2/a^2=1
\n" ); document.write( "using given point on parabola (1,7) to solve for a
\n" ); document.write( "(7-2)^2/a^2-(1+3)^2/a^2=1
\n" ); document.write( "25/a^2-16/a^2=1
\n" ); document.write( "9/a^2=1
\n" ); document.write( "a^2=9
\n" ); document.write( "a=3
\n" ); document.write( "b=a=3
\n" ); document.write( "Equation of given hyperbola:
\n" ); document.write( "(y-2)^2/9-(x+3)^2/9=1
\n" ); document.write( "..
\n" ); document.write( "Asymptotes:
\n" ); document.write( "Asymptotes are straight lines thru the center of the hyperbola of the standard form:
\n" ); document.write( "y=mx+b, m=slope, b=y-intercept
\n" ); document.write( "for slope=1
\n" ); document.write( "2=1*-3+b
\n" ); document.write( "b=5
\n" ); document.write( "equation of asymptote
\n" ); document.write( "y=x+5
\n" ); document.write( "..
\n" ); document.write( "for slope=-1
\n" ); document.write( "2=-1*-3+b
\n" ); document.write( "b=-1
\n" ); document.write( "equation of asymptote
\n" ); document.write( "y=-x-1
\n" ); document.write( "..
\n" ); document.write( "See graph as a visual check on answers:
\n" ); document.write( "..
\n" ); document.write( "y=±(9+(x+3)^2)^.5+2
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\n" ); document.write( "..
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