document.write( "Question 531433: solve by substitution method\r
\n" ); document.write( "\n" ); document.write( "0.1x+0.3y=-0.7
\n" ); document.write( "0.9x-0.2y=8.2
\n" ); document.write( "

Algebra.Com's Answer #350451 by stanbon(75887)\"\" \"About 
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solve by substitution method
\n" ); document.write( "0.1x+0.3y=-0.7
\n" ); document.write( "0.9x-0.2y=8.2
\n" ); document.write( "----
\n" ); document.write( "1st: Get rid of all those decimals
\n" ); document.write( "x + 3y = -7
\n" ); document.write( "9x - 2y = 82
\n" ); document.write( "-----
\n" ); document.write( "Multiply the 1st equation by \"9\" to get:
\n" ); document.write( "9x + 27y = -63
\n" ); document.write( "9x - 2y = 82
\n" ); document.write( "----
\n" ); document.write( "Subtract and solvd for \"y\":
\n" ); document.write( "29y = 145
\n" ); document.write( "y = 5
\n" ); document.write( "----
\n" ); document.write( "Solve for \"x\":
\n" ); document.write( "x + 3y = -7
\n" ); document.write( "x + 15 = -7
\n" ); document.write( "x = -22/3
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\n" ); document.write( "cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "=============
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