document.write( "Question 531391: Suppose $4000.00 is invested at interest rate K, compounded continuously, and grows to $4943.71 in 6 years:
\n" ); document.write( "Find the interest rate.
\n" ); document.write( "Find the exponential growth function.
\n" ); document.write( "Find the balance after 10 years.
\n" ); document.write( "Find the doubling time.
\n" ); document.write( "

Algebra.Com's Answer #350427 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Suppose $4000.00 is invested at interest rate K, compounded continuously, and grows to $4943.71 in 6 years:
\n" ); document.write( "---
\n" ); document.write( "A(t) = Ao*e^(rt)
\n" ); document.write( "4943.71 = 4000*e^(6K)
\n" ); document.write( "e^(6K) = 1.2359
\n" ); document.write( "6K = ln(1.2359)
\n" ); document.write( "K = 0.0353
\n" ); document.write( "-----------------------
\n" ); document.write( "Find the interest rate:::3.53%
\n" ); document.write( "Find the exponential growth function.A(t) = 4000*e^(0.0353t)
\n" ); document.write( "----------------
\n" ); document.write( "Find the balance after 10 years.A(10) =4000*e^(0.353) = $5693.32
\n" ); document.write( "----------------------------
\n" ); document.write( "Find the doubling time.
\n" ); document.write( "e^(0.0353t) = 2
\n" ); document.write( "0.0353t = ln2
\n" ); document.write( "t = 19.64 years
\n" ); document.write( "=================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "
\n" ); document.write( "
\n" );