document.write( "Question 531391: Suppose $4000.00 is invested at interest rate K, compounded continuously, and grows to $4943.71 in 6 years:
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document.write( "Find the interest rate.
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document.write( "Find the exponential growth function.
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document.write( "Find the balance after 10 years.
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document.write( "Find the doubling time. \n" );
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Algebra.Com's Answer #350427 by stanbon(75887) ![]() You can put this solution on YOUR website! Suppose $4000.00 is invested at interest rate K, compounded continuously, and grows to $4943.71 in 6 years: \n" ); document.write( "--- \n" ); document.write( "A(t) = Ao*e^(rt) \n" ); document.write( "4943.71 = 4000*e^(6K) \n" ); document.write( "e^(6K) = 1.2359 \n" ); document.write( "6K = ln(1.2359) \n" ); document.write( "K = 0.0353 \n" ); document.write( "----------------------- \n" ); document.write( "Find the interest rate:::3.53% \n" ); document.write( "Find the exponential growth function.A(t) = 4000*e^(0.0353t) \n" ); document.write( "---------------- \n" ); document.write( "Find the balance after 10 years.A(10) =4000*e^(0.353) = $5693.32 \n" ); document.write( "---------------------------- \n" ); document.write( "Find the doubling time. \n" ); document.write( "e^(0.0353t) = 2 \n" ); document.write( "0.0353t = ln2 \n" ); document.write( "t = 19.64 years \n" ); document.write( "================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |