document.write( "Question 531211: An air rescue plane averages 300 miles per hour in still air. It carries fuel for 5 hours of flying time. If, upon takeoff, it encounters a head wind of 30 miles per hour, how far can it fly and return safely? (Assume that the wind remains constant) \n" ); document.write( "
Algebra.Com's Answer #350372 by ankor@dixie-net.com(22740)\"\" \"About 
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An air rescue plane averages 300 miles per hour in still air.
\n" ); document.write( " It carries fuel for 5 hours of flying time.
\n" ); document.write( "If, upon takeoff, it encounters a head wind of 30 miles per hour, how far can it fly and return safely?
\n" ); document.write( " (Assume that the wind remains constant)
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\n" ); document.write( "300 - 30 = 270 mph the ground speed against the wind
\n" ); document.write( "300 + 30 = 330 mph the ground speed with the wind
\n" ); document.write( ":
\n" ); document.write( "let d = the one way distance to point of no return
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\n" ); document.write( "Write a time equation, time = dist/speed
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\n" ); document.write( "Outbound time + return time = 5 hrs
\n" ); document.write( "\"d%2F270\" + \"d%2F330\" = 5
\n" ); document.write( "multiply by 2970 to get rid of the denominators, results
\n" ); document.write( "11d + 9d = 2970(5)
\n" ); document.write( "20d = 14850
\n" ); document.write( "d = \"14850%2F20\"
\n" ); document.write( "d = 742.5 mi, but it says \"safely\", you would never cut it that close; I would say 650 max.
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\n" ); document.write( "Confirm this by finding the actual time for each trip
\n" ); document.write( "742.5/270 = 2.75 hrs
\n" ); document.write( "742.5/330 = 2.25 hrs
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\n" ); document.write( "totals time: 5 hrs \n" ); document.write( "
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