document.write( "Question 531212: 2(2x+5/3x)^2 -5 = 9(2x+5/3x)\r
\n" ); document.write( "\n" ); document.write( "This problem is supposed to be solved by substituting a variable like U for (2x+5/3x).Write in standard form. (2U^2 -9U -5=0) Factor. (2U+1)(U-5). Set to zero. U=-1/2 and U=5. But, when I try to set these values to (2x+5/3x)to solve for x, the answers don't fit into the original equation as they should. What in the world is wrong? Thanks so much for your help. \n" ); document.write( "
Algebra.Com's Answer #350371 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
2(2x+5/3x)^2 -5 = 9(2x+5/3x)
\n" ); document.write( "---
\n" ); document.write( "Let w = (2x+5)/(3x)
\n" ); document.write( "----
\n" ); document.write( "2w^2 - 9w -5 = 0
\n" ); document.write( "2w^2-10w+w-5 = 0
\n" ); document.write( "2w(w-5)+(w-5) = 0
\n" ); document.write( "(w-5)(2w+1) = 0
\n" ); document.write( "w = 5 or w = -1/2
\n" ); document.write( "----
\n" ); document.write( "solve for \"x\":
\n" ); document.write( "If w = 5 you get:
\n" ); document.write( "(2x+5)/(3x) = 5
\n" ); document.write( "2x+5 = 15x
\n" ); document.write( "13x = 5
\n" ); document.write( "x = 5/13
\n" ); document.write( "------
\n" ); document.write( "If x = -1/2 you get:
\n" ); document.write( "(2x+5)/(3x) = -1/2
\n" ); document.write( "4x+10 = -3x
\n" ); document.write( "7x = -10
\n" ); document.write( "x = -10/7
\n" ); document.write( "================
\n" ); document.write( "cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "================ \n" ); document.write( "
\n" );