document.write( "Question 531208: Tom can mow his lawn in 6 hours. If Julia helps Tom, the job gets done in 2 hours. How many hours would it take Julia working alone? \n" ); document.write( "
Algebra.Com's Answer #350366 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Tom can mow his lawn in 6 hours. If Julia helps Tom, the job gets done in 2 hours. How many hours would it take Julia working alone?
\n" ); document.write( "------
\n" ); document.write( "Tom's rate: 1/6 job/hr
\n" ); document.write( "Together rate: 1/2 job/hr
\n" ); document.write( "Julia rate: 1/x job/hr
\n" ); document.write( "----------------
\n" ); document.write( "Equation:
\n" ); document.write( "rate + rate = together rate
\n" ); document.write( "1/6 + 1/x = 1/2
\n" ); document.write( "Multiply thru by 12x
\n" ); document.write( "2x + 12 = 6x
\n" ); document.write( "4x = 12
\n" ); document.write( "x = 3 hrs (time for Julia to do the job alone)
\n" ); document.write( "============
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "
\n" );