document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=530611>Question 530611</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangular lawn is measured at y meters wide by (2y+5) meters long. A) write an expression for the perimeter of the lawn.  B) the perimeter is measured at 52 meters. Use this information to form an equation. C) solve this equation to find the length and width of the lawn </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #350350 by </B><A HREF=/tutors/aboutme.mpl?userid=boilpoil><B>boilpoil(127)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=boilpoil><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=boilpoil><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=350350\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A) Let X represent the perimeter of the lawn<BR>\n" );
document.write( "X = 2(2y+5)+2y<BR>\n" );
document.write( "  = 4y+10+2y<BR>\n" );
document.write( "  = 6y+10\r<BR>\n" );
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document.write( "B) 6y+10=x and x=52<BR>\n" );
document.write( "   6y+10=52\r<BR>\n" );
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document.write( "C) 6y=42<BR>\n" );
document.write( "    y=7(meters)\r<BR>\n" );
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document.write( "Length of the lawn<BR>\n" );
document.write( "=2[2(7)+5]<BR>\n" );
document.write( "=2[14+5]<BR>\n" );
document.write( "=2[19]<BR>\n" );
document.write( "=38(meters) </SPAN>\n" );
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