document.write( "Question 531021: I'm trying to figure out the formula for this word problem. If I can figure out the formula for mixtures I should be able to do the entire worksheet.\r
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document.write( "Sample Problem: A Chemist has a solution that is 12% acid and another solution that is 42% acid. She wants 10L of solution that is 30% acid. How much of each solution should she mix? \n" );
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Algebra.Com's Answer #350306 by oberobic(2304)![]() ![]() ![]() You can put this solution on YOUR website! With solution problems you need to determine how much 'pure' stuff you have or need. \n" ); document.write( ". \n" ); document.write( "The chemist needs 10 liters of a 30% acid. .3*10 = 3 liters of 'pure' acid in a solvent (likely water). \n" ); document.write( ". \n" ); document.write( "She has 12% acid and 42% acid to mix together. \n" ); document.write( ". \n" ); document.write( "x = liters of 12% acid \n" ); document.write( "y = liters of 42% acid \n" ); document.write( "x+y =10 \n" ); document.write( "so \n" ); document.write( "x = 10-y \n" ); document.write( "or \n" ); document.write( "y = 10 - x \n" ); document.write( ". \n" ); document.write( ".12*x + .42*y = .3*10 \n" ); document.write( ". \n" ); document.write( "multiply by 100 to eliminate decimals \n" ); document.write( ". \n" ); document.write( "12x + 42y = 30*10 \n" ); document.write( ". \n" ); document.write( "substitute for x \n" ); document.write( ". \n" ); document.write( "12(10-y) + 42y = 300 \n" ); document.write( "120 -12y + 42y = 300 \n" ); document.write( "30y = 180 \n" ); document.write( "y = 6 \n" ); document.write( ". \n" ); document.write( "Answer: Mix 6 liters of 42% acid and 4 liters of 12% acid. \n" ); document.write( ". \n" ); document.write( "Check the amount of pure acid to be sure this answer is correct. \n" ); document.write( ".42*6 = 2.52 \n" ); document.write( ".12*4 = 0.48 \n" ); document.write( "2.52 + .48 = 3.0 \n" ); document.write( "Correct. \n" ); document.write( ". \n" ); document.write( "Done. \n" ); document.write( " |