document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=530945>Question 530945</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1/3^(2x+6)=9^(x-4)\r<BR>\n" );
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document.write( "really need steps for this.  It's been years since I've had Algebra and trying to help kiddo.  Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #350297 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=350297\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1/3 = 3^(-1) ___ 9 = 3^2\r<BR>\n" );
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document.write( "[3^(-1)]^(2x + 6) = (3^2)^(x - 4)\r<BR>\n" );
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document.write( "3^(-2x - 6) = 3^(2x - 8)\r<BR>\n" );
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document.write( "-2x - 6 = 2x - 8 ___ 2 = 4x </SPAN>\n" );
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