document.write( "Question 530977: The length of a rectangle is twice its width. The perimeter is 30 meters. Find the length and the width. \n" ); document.write( "
Algebra.Com's Answer #350280 by oberobic(2304)![]() ![]() ![]() You can put this solution on YOUR website! L = 2W \n" ); document.write( ". \n" ); document.write( "P = 30 \n" ); document.write( "P = 2(L+W) \n" ); document.write( "L + W = 15 \n" ); document.write( "L = 15-W \n" ); document.write( ". \n" ); document.write( "L=L \n" ); document.write( "so \n" ); document.write( "2W = 15-W \n" ); document.write( "3W = 15 \n" ); document.write( "W = 5 \n" ); document.write( ". \n" ); document.write( "L = 2W \n" ); document.write( "L = 10 \n" ); document.write( ". \n" ); document.write( "Check the perimeter. \n" ); document.write( "2(L-W) = 2(10+5) = 30 m \n" ); document.write( "Correct. \n" ); document.write( ". \n" ); document.write( "Answer: Length = 10 m, and width = 5 m. \n" ); document.write( ". \n" ); document.write( "Done. \n" ); document.write( " |