document.write( "Question 52335: solve and check please...\r
\n" ); document.write( "\n" ); document.write( "x/2x+2=2x/4x+4+2x-3/x+1
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Algebra.Com's Answer #35028 by darq(90)\"\" \"About 
You can put this solution on YOUR website!
\"x%2F2x+%2B+2+=+2x%2F4x+%2B+4+%2B+2x-+3%2Fx+%2B+1\"
\n" ); document.write( "\"1%2F2+%2B+2+=+1%2F2+%2B+4+%2B+2x-+3%2Fx+%2B+1\"
\n" ); document.write( "\"2+=+2x+-+3%2Fx+%2B+5\"
\n" ); document.write( "\"0+=+2x+%2B+3+-+3%2Fx\"
\n" ); document.write( "multiply both sides with x
\n" ); document.write( "\"0+=+2x%5E2+%2B3x+-+3\"
\n" ); document.write( "divide both sides with 2
\n" ); document.write( "\"0+=+x%5E2+%2B+3%2F2%2Ax+-+3%2F2\"
\n" ); document.write( "add 33/16 to both sides
\n" ); document.write( "\"33%2F16+=+x%5E2+%2B+3%2F2%2Ax+%2B+9%2F16\"
\n" ); document.write( "\"33%2F16+=+%28x%2B3%2F4%29%5E2\"
\n" ); document.write( "\"%2B-+sqrt%2833%2F16%29+=+x%2B3%2F4\"
\n" ); document.write( "\"%2B-+sqrt%2833%29%2F4+-+3%2F4+=+x\"
\n" ); document.write( "\"%28%2B-+sqrt%2833%29-3%29%2F4+=+x\"\r
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\n" ); document.write( "\n" ); document.write( "so x can be both \"%28sqrt%2833%29-3%29%2F4\" or \"%28-sqrt%2833%29-3%29%2F4\"
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