document.write( "Question 530936: My math question is:
\n" ); document.write( "Steve and Jordan are riding bikes. Jordan is riding at 7 mph and Steve is riding at 6 mph. If Jordan is 5 miles behind Steve, how long will it take for Jordan to catch up to Steve?
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Algebra.Com's Answer #350263 by stanbon(75887)\"\" \"About 
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Steve and Jordan are riding bikes. Jordan is riding at 7 mph and Steve is riding at 6 mph. If Jordan is 5 miles behind Steve, how long will it take for Jordan to catch up to Steve?\r
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\n" ); document.write( "Jordan DATA:
\n" ); document.write( "rate = 7 mph ; distance = x miles ; time = x/7 hrs = (60/7)x minutes
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\n" ); document.write( "Steve DATA:
\n" ); document.write( "rate = 6 mph ; distance = x-5 miles ; time = (x-5)/6 hrs = 10*(x-5) minutes
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\n" ); document.write( "Equation:
\n" ); document.write( "(60/7)x = 10(x-5)
\n" ); document.write( "60x = 70x - 350
\n" ); document.write( "10x = 350
\n" ); document.write( "x = 35 miles
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\n" ); document.write( "Time Jordan needed to catch Steve:
\n" ); document.write( "(60/7)x = 60/7 * 35 = 300 minutes = 5 hours
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\n" ); document.write( "Quicker method:
\n" ); document.write( "At 7 mph Jordan gains 1 mile in 1 hour
\n" ); document.write( "So after 5 hours Jordan has caught up with Steve.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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