document.write( "Question 530875: Do the following equations intersect and if so what is the point of intersection(In fraction form):
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Algebra.Com's Answer #350242 by oberobic(2304)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( ". \n" ); document.write( "To find the intersection, begin by getting both equations into standard form. \n" ); document.write( ". \n" ); document.write( "y=4/3x+16/3 \n" ); document.write( "-4/3x +y = 16/3 \n" ); document.write( "multiply by 3 \n" ); document.write( "-4x + 3y = 16 \n" ); document.write( ". \n" ); document.write( "y=3/2x+1 \n" ); document.write( "-3/2x + y = 1 \n" ); document.write( "multiply by 2 \n" ); document.write( "-3x + 2y = 2 \n" ); document.write( ". \n" ); document.write( "Now we have a system of equations \n" ); document.write( ". \n" ); document.write( "-4x + 3y = 16 \n" ); document.write( "-3x + 2y = 2 \n" ); document.write( ". \n" ); document.write( "Multiply the first equation by 3 and the second by 4, then subtract. \n" ); document.write( ". \n" ); document.write( "-12x + 9y = 48 \n" ); document.write( "-12x + 8y = 8 \n" ); document.write( "-------------- \n" ); document.write( "y = 40 \n" ); document.write( ". \n" ); document.write( "substitute to find 'x' \n" ); document.write( ". \n" ); document.write( "-4x + 120 = 16 \n" ); document.write( "-4x = -104 \n" ); document.write( "x = 26 \n" ); document.write( ". \n" ); document.write( "The point of intersection is (26,40). \n" ); document.write( " \n" ); document.write( " |