Algebra.Com's Answer #350239 by oberobic(2304)  You can put this solution on YOUR website! x = a number \n" );
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document.write( "It exceeds it's reciprocal by 3 \n" );
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document.write( "x = 1/x + 3 \n" );
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document.write( "multiply both sides by x to eliminate the fraction \n" );
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document.write( "x^2 = 1 + 3x \n" );
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document.write( "x^2 -3x -1 = 0 \n" );
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document.write( "This will not factor, but it can be solved by the quadratic equation. \n" );
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document.write( " Solved by pluggable solver: SOLVE quadratic equation with variable | \n" );
document.write( "Quadratic equation (in our case ) has the following solutons: \n" );
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document.write( " For these solutions to exist, the discriminant should not be a negative number. \n" );
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document.write( " First, we need to compute the discriminant : . \n" );
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document.write( " Discriminant d=13 is greater than zero. That means that there are two solutions: . \n" );
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document.write( " Quadratic expression can be factored: \n" );
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document.write( " Again, the answer is: 3.30277563773199, -0.302775637731995.\n" );
document.write( "Here's your graph: \n" );
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